![]() ![]() MyObject.Something() // Error: The property 'Something' does not exist on value of type 'Object'. Objects do not allow the same flexibility. Specifically, properties of any name can be accessed throughĪn Any value and Any values can be called as functions or Minimal static type checking is performed for operations on Any A value of theĪny type supports the same operations as a value in JavaScript and The Any type is used to represent any JavaScript value. These types introduce various static constraints on One type that can represent any JavaScript value with no constraints.Īll other types are categorized as primitive types, object types, or From the TypeScript spec (section 3):Īll types in TypeScript are subtypes of a single top type called theĪny type. Object appears to be a more specific declaration than any. X will have the same available properties within all of these functions, but it's a type error to call d with a primitive: b("foo") //Okay Since type compatibility in TypeScript is based on structural subtyping, not nominal subtyping, c ends up being the same as b because they have the same interface: the Object interface.Īnd that's why a.doSomething() // Ok: the compiler trusts you on thatī.doSomething() // Error: Object has no doSomething memberĬ.doSomething() // Error: c neither has doSomething nor inherits it from ObjectĪnd why a.toString() // Ok: whatever, dude, have it your wayī.toString() // Ok: toString is defined in ObjectĬ.toString() // Ok: c inherits toString from Object c extends Object, like anything else in TypeScript, but adds no members.The app has a few pre-made lists like Today, Tomorrow, Upcoming, and. you can create multiple lists for multiple aspects of your life. First, go ahead and install the Any.do app on your smartphone from the Google Play store. It's still JavaScript, so everything extends Object Here’s how to use Any.do to make the most out of it. b has the Object interface, so ONLY the members defined in that interface are available for b.Basically, you're telling the compiler to " back off, I know what I'm doing, so just trust me" a has no interface, it can be anything, the compiler knows nothing about its members so no type checking is performed when accessing/assigning both to it and its members.When you write something like this let a: any Bit old, but doesn't hurt to add some notes. ![]()
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